Helmholtz free energy

Thermodynamic potentials
Internal energy	$U (S, V)$
Helmholtz free energy	$A (T, V) = U - T S$
Enthalpy	$H (S, p) = U + P V$
Gibbs free energy	$G (T, p) = U + P V - T S$
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In Hermann von Helmholtz and is denoted by the letter A (from the German “Arbeit” or work), or the letter F . The IUPAC recommends the letter A as well as the use of name Helmholtz energy;^[1] in physics, A is called the Helmholtz function or simply “free energy”.

While chemistry, the isobaric restriction on that quantity is sometimes inconvenient. For example, in explosives research, Helmholtz free energy is often used since explosive reactions by their nature induce pressure changes.

Definition

The Helmholtz energy is defined as:

$A \equiv U-TS\,$ ^[2]

where

A is the Helmholtz free energy (joules, CGS: ergs),
U is the internal energy of the system (SI: joules, CGS: ergs),
T is the absolute temperature (kelvins),
S is the entropy (SI: joules per kelvin, CGS: ergs per kelvin).

Mathematical development

From the first law of thermodynamics we have:

${\rm d}U = \delta Q - \delta W\,$

where $U$ is the internal energy, $δ Q$ is the energy added by heating and $δ W = p d V$ is the work done by the system. From the reversible process we may say that $δ Q = T d S$ . Differentiating the expression for $A$ we have:

${\rm d}A = {\rm d}U - (T{\rm d}S + S{\rm d}T)\,$

$= (T{\rm d}S - p\,{\rm d}V) - T{\rm d}S - S{\rm d}T\,$

$= - p\,{\rm d}V - S{\rm d}T\,$

For a process which is not reversible, the energy will be smaller than its equilibrium value so we may say that, in general,

${\rm d}A \le - p\,{\rm d}V - S{\rm d}T\,$

It is seen that if a thermodynamic process is isothermal (i.e. occurs at constant temperature), then $d T = 0$ and thus

${\rm d}A \le -\delta W\,$

The negative of the change in the Helmholtz energy is the maximum work attainable from the system in an isothermal process. In more mathematical terms, the integral of $- d A$ over any isotherm in state space is the maximum work attainable from the system.

If, in addition the volume is held constant as well, the above equation becomes:

${\rm d}A \le 0\,$

with the equality holding at equilibrium. It is seen that the Helmholtz energy for a general system in which the temperature and volume are held constant will continuously decrease to its minimum value, which it maintains at equilibrium.

In a more general form, the first law describes the internal energy with additional terms involving the chemical potential and the number of particles of various types. The differential statement for $d A$ is then:

${\rm d}A \le - p\,{\rm d}V - S{\rm d}T + \sum_i \mu_i \,{\rm d}N_i\,$

where $μ i$ is the chemical potential for an i-type particle, and $N i$ is the number of such particles. With this definition, we may say that the negative of the Helmholtz energy is the maximum amount of work energy available from a system in which the initial and final states have the same temperature and number of particles. Further generalizations will add even more terms whose extensive differential term must be set to zero in order for the interpretation of the Helmholtz energy to hold.

In statistical mechanics, the relationship between the Helmholtz free energy and the partition function is fundamental, and is used to calculate the thermodynamic properties of matters; see configuration integral for more details.

Generalized Helmholtz energy

In the more general case, the mechanical term ( $p d V$ ) must be replaced by the product of the volume times the stress times an infinitesimal strain:^[3]

${\rm d}A \le V\sum_{ij}\sigma_{ij}\,{\rm d}\varepsilon_{ij} - S{\rm d}T + \sum_i \mu_i \,{\rm d}N_i\,$

where $σ i j$ is the stress tensor, and $\varepsilon_{ij}$ is the strain tensor. In the case of linear Hooke's Law, the stress is related to the strain by:

σ i j = C i j k l ε k l

where we are now using Einstein notation for the tensors, in which repeated indices in a product are summed. We may integrate the expression for $d A$ to obtain the Helmholtz energy:

$A = \frac{1}{2}VC_{ijkl}\epsilon_{kl}^2 - ST + \sum_i \mu_i N_i\,$

$= \frac{1}{2}V\sigma_{ij}\epsilon_{ij} - ST + \sum_i \mu_i N_i\,$

References

^ Gold Book. IUPAC. Retrieved on 2007-11-04.
^ Levine, Ira. N. (1978). "Physical Chemistry" McGraw Hill: University of Brooklyn
^ Landau, L. D.; Lifshitz, E. M. (1986). Theory of Elasticity (Course of Theoretical Physics Volume 7), (Translated from Russian by J.B. Sykes and W.H. Reid), Third ed., Boston, MA: Butterworth Heinemann. ISBN 0-7506-2633-X.

Helmholtz free energy

Definition

Mathematical development

Generalized Helmholtz energy

See also

References

Further reading